Weird math

[bearmick]

Write any 3 digit number next to itself. For example, 369369.

The resultant 6 digit number is divisible by 7, 11 and 13.

And if you progressively divide the six digit number by 7, 11, and 13, the final result is the original 3 digit number.

369369 ÷ 7 = 52767
52767 ÷ 11 = 4797
4797 ÷ 13 = 369.

 

[Omeletpants]

Oh, look at the big brain

 

[Omeletpants]

 

[BearFanJohn]

Write any 3 digit number next to itself. For example, 369369.

The resultant 6 digit number is divisible by 7, 11 and 13.

And if you progressively divide the six digit number by 7, 11, and 13, the final result is the original 3 digit number.

369369 ÷ 7 = 52767
52767 ÷ 11 = 4797
4797 ÷ 13 = 369.

Shit like this makes my brain hurt.

 

[DaaBears]

Interesting. It doesn't matter obviously tho the order that you divide them. It can be 11, 7, 13 for example.

 

[bearmick]

Interesting. It doesn't matter obviously tho the order that you divide them. It can be 11, 7, 13 for example.

Yes that would always produce the same result. Same math in a different order.

 

[DaaBears]

Yes that would always produce the same result. Same math in a different order.

Of course.

 

[TL1961]

I like it.

 

[Xuder O'Clam]

Write any 3 digit number next to itself. For example, 369369.

The resultant 6 digit number is divisible by 7, 11 and 13.

And if you progressively divide the six digit number by 7, 11, and 13, the final result is the original 3 digit number.

369369 ÷ 7 = 52767
52767 ÷ 11 = 4797
4797 ÷ 13 = 369.

Divisible by 1001 also. Which is the product of 7, 11, and 13. Therefore, if you multiply any 3 digit number by 1001, you get a 6 digit number with first three numbers repeated.



Also

Any multiple of 9, when broken down by adding the individual digits of the number to one digit (digital root), the final number will always equal 9.

Examples

9x2=18
1+8=9



9x6983=62847
6+2+8+4+7=27
2+7=9


9x899754398=8097789582
8+0+9+7+7+8+9+5+8+2=63
6+3=9

 

[bearmick]

The number 6174 is absolutely crazy.

Kaprekar's Constant.