Mathematically that would likely be or be tied with the best record in the division unless the two losses were to the same team or in the below scenarios.
Scneario 1: A team wins 5 games in division
Bears at 4-2 (2 Wins against C. 1 Win/Loss against A. 1 Win/Loss against B)
Team A: 1 loss to Bears, win every other game. 5-1
Team B: 1 loss to Bears, 2 loss to Team A at minimum. Wins both games against C. 3-3
Team C: Loses every game. 0-6.
Scneario 2: A team wins 6 games in division
Bears at 4-2 (2 Wins against C. 2 Loss against A. 2 Win against B)
Team A: 6-0
Team B: 2-4 or 1-5 (two loss to A and Bears)
Team C: 0-6 or 1-5
Scenario 3: Two or Three teams at 4-2.
Bears at 4-2 (2 Wins against C. 1 Win/Loss against A. 1 Win/Loss against B)
Team A: 4-2 (1 win/loss to bears, 1 win/loss to B, 2 wins to C)
Team B: 4-2 or 3-3 (1 win/loss to Bears, 1 win/loss to A, 2 wins to C or 1 win/loss to C)
Team C: 0-6 or 1-5 (Lose except one game to B)
Scenario 4: Only 1 team at 4-2
Bears at 4-2 (2 Wins against C. 1 Win/Loss against A. 1 Win/Loss against B or 2 win against C, 2 win against A, 2 loss vs B)
Team A: 3-3 (1 win vs Bears, 1 win/loss to B, 1 win/loss to C)
Team B: 3-3 (1 win/loss to Bears, 1 win/loss to A, 1 win/loss to C)
Team C: 2-4 (2 loss to Bears, 1 win/loss to A, 1 win/loss to B)
The Alternate
Team A: 3-3 (2 loss to Bears, 1 win/loss to B, 2 win to C)
Team B: 3-3 (2 win to Bears, 1 win/loss to A, 2 loss to C)
Team C: 2-4 (2 loss to Bears, 2 win to B, 2 loss to A)